How do you solve #v^2+7v+12=0#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer smendyka Nov 11, 2016 #v = -4# and #v = -3# Explanation: #v^2 + 7v + 12 = 0# #(v + 4)(v + 3) = 0# Then solve for each term of the quadratic: 1) #((v + 4)(v + 3))/(v + 3) = 0/(v + 3)# #v + 4 = 0# #v + 4 - 4 = 0 - 4# #v = -4# 2) #((v + 4)(v + 3))/(v + 4) = 0/(v + 4)# #v + 3 = 0# #v + 3 - 3 = 0 - 3# #v = -3# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2188 views around the world You can reuse this answer Creative Commons License