Question

How do you sketch the angle whose terminal side in standard position passes through (4,-3) and how do you find sin and cos?

Answer 1

`sin t = - 3/5`
`cos t = 4/5`

Explanation:

consider the right triangle 0AB with
OA = 4 ; AB = -3
Then, hypotenuse OB = 5 (Ratio 3:4:5)
We have, calling t the angle <AOB:
`cos t = OA/OB = 4/5`
`sin t = -AB/OB = - 3/5`