How do you solve #(3x)/5 = x - 1#? Algebra Properties of Real Numbers Applications of Reciprocals 1 Answer Anjali G Nov 12, 2016 #3/5x=x-1# Subtract x from each side: #-2/5x=-1# Multiply each side by #-5/2# #x=5/2# Answer link Related questions Why are reciprocals useful when dividing rational expressions? What is the difference between a reciprocal of a number and a opposite of the number? What is the reciprocal of -2/3? Does zero have a reciprocal? How do you solve for Mayra's speed if Mayra runs 3 and a quarter miles in one-half hour? How do you solve for a if #F=7 1/3# and #m=1/5# given Newton's second law states the #a=F/m#... How do you evaluate #x/y# for #x=3/8# and #y=4/3#? What is the weight of 20 packets if each packet weighs #32/5#kg? What is the reciprocal of square root of 2? What is the opposite and reciprocal of 200? See all questions in Applications of Reciprocals Impact of this question 3692 views around the world You can reuse this answer Creative Commons License