Question

How do you use the chain rule to differentiate `root11(sinx)`?

Answer 1

`root(11)sinx = (sinx)^(1/11)`

Explanation:

So the derivaitive is

`1/11(sinx)^(1/11-1) * d/dx(sinx) = 1/11 cosx (sinx)^(-10/11)`

`= cosx/(11root(11)(sinx)^10)`