How do you write the equation #-x+3y=7# in polar form?

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Answer 1 · 2016-11-12T22:21:24

Please see the explanation

Substitute #rcos(theta)# or x and #rsin(theta)# for y:

#-rcos(theta) + 3rsin(theta)# = 7

Move the common factor r outside ()s:

#r(3sin(theta) - cos(theta)) = 7#

Divide both sides by #(3sin(theta) - cos(theta))#

#r = 7/(3sin(theta) - cos(theta))#

Here is a polar graph of the above:

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