Question

What is the perimeter of a triangle with corners at `(7 ,3 )`, `(1 ,5 )`, and `(2 ,1 )`?

Answer 1

Perimeter of the triangle is `15.8329`

Explanation:

As the corners are `A(7,3)`, `B(1,5)` and `C(2,1)`, the three sides of a triangle are

`a=sqrt((2-1)^2+(1-5)^2)=sqrt(1+16)=sqrt17=4.1231`

`b=sqrt((7-2)^2+(3-1)^2)=sqrt(25+4)=sqrt29=5.3852`

`c=sqrt((7-1)^2+(3-5)^2)=sqrt(36+4)=sqrt40=6.3246`

and perimeter is `4.1231+5.3852+6.3246=15.8329`