How do you combine #1/2+2/(x+2)#?

1 Answer
Nov 14, 2016

#(x+6)/(2x+4)#

Explanation:

A fraction consists of

#("numerator")/("denominator") -> ("count")/("size indicator of what you are counting")#

#color(blue)("Important fact 1")#
You can not DIRECTLY add or subtract the counts unless the size indicators are the same

#color(blue)("Important fact 2")#
Multiply by 1 and you do not change the value. However, 1 comes in many forms so you can change the way numbers look but not change their actual value.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)([1/2color(red)(xx1)]+[2/(x+2)color(red)(xx1)]#

Is the same as:

#color(blue)([1/2color(red)(xx(x+2)/(x+2))]+[2/(x+2)color(red)(xx2/2)] #

#(x+2)/(2(x+2))+4/(2(x+2))#

#(x+2+4)/(2(x+2)) " "=" "(x+6)/(2x+4)#