How many molecules are present in 1.0 x 103g of water? (Answer with correct number of sig figs)

1 Answer
anor277 · Monzur R.
Nov 14, 2016

#"Number of water molecules"#
#= (1.0xx10^3*g)/(18.01*g*mol^-1)xx6.022xx10^23*mol^-1#

Explanation:

We use #"Avogadro's number"# #=# #6.022 xx 10^23 *mol"^-1#.

And since the units clearly cancel out we get the answer as a dimensionless number.

I leave it to you to determine the correct number of significant figures.

Related questions
See all questions in Significant Figures
Impact of this question
2390 views around the world
You can reuse this answer
Creative Commons License