Question

How do you differentiate `g(t)= 7/sqrt(t)`?

Answer 1

`g'(t)=(-7)/(2t^(3/2))`

Explanation:

`g(t)=7/(sqrtt)`

This can be solved multiple ways, such as using the quotient rule, or using the power rule. I prefer the power rule so I will rewrite `g(t)`:

`g(t)=7/(t^(1/2))`
`g(t)=7t^(-1/2)`

Now to differentiate `g(t)`, use the power rule:

`g'(t)=(-1/2)(7)(t^(-3/2))`
`g'(t)=(-7/2)(t^(-3/2))`

`g'(t)=(-7)/(2t^(3/2))`