Question

How do you find the derivative of `y = (lnx)/(ln3)`?

Answer 1

Please see the explanation.

Explanation:

You treat `1/ln(3)` as any other constant:

`y = (1/ln(3))ln(x)`

`y' = (1/ln(3))1/x`

Using a property of logarithms, `log_b(a)(c) = log_b(a^c)`, this can be simplified to:

`y' = 1/ln(3^x)`