How do you find the exact values of #sintheta# and #tantheta# when #costheta=1#?

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Answer 1 · 2016-11-16T18:50:30

Please see the explanation.

Given #cos(theta) = 1#

To find #sin(theta), use the identity:

#sin^2(theta) + cos^2(theta) = 1#

#sin^2(theta) + 1^2 = 1#

#sin^2(theta) = 0#

#sin(theta) = 0#

To find #tan(theta)#, use the identity:

#tan(theta) = sin(theta)/cos(theta)#

#tan(theta) = 0/1#

#tan(theta) = 0#