Question

If `16 L` of a gas at room temperature exerts a pressure of `7 kPa` on its container, what pressure will the gas exert if the container's volume changes to `2 L`?

Answer 1

The pressure is `=56kPa`

Explanation:

Use Boyle's Law

`P_1V_1=P_2V_2`

`P_1=7kPa`

`V_1=16l`

`V_2=2l`

So, `P_2=(P_1V_1)/V_2=7*16/2=56 kPa`