Question

The gas inside of a container exerts `15 Pa` of pressure and is at a temperature of `220 ^o C`. If the temperature of the gas changes to `10 ^oC` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

The new pressure of the gas is 0.68 Pascals.

Explanation:

Considering the ideal gas equation
`PV=RT`(n=1)
We can know from the above equation that pressure is directly proportional to the temperature.
`=>P prop T`
this means `(P_1)/(P_2) = (T_1)/(T_2)`
calculating with given values we get,
`=>(15 Pa)/(P_2)=(220^oC)/(10^oC)`
So `:.` the new pressure `P_2 = 0.68` Pascals`=6.71xx10^-6 atm=5.1xx10^-3`torr.