How do you find the center and radius of the circle given #x^2+(y-sqrt3)^2+4x=25#?
1 Answer
Please see the explanation for steps leading to:
The center is
Explanation:
The standard form for the equation of a circle is:
where
Please notice that (y - sqrt(3))^2 is already in that form and we can see that
Add
When we expand the x square in the standard form we get:
We can find the value of h by setting the middle term from the standard form equal to the middle term of our equation:
This means that we can substitute
Combine the right side:
Write the 29 as
In this form we can see the center and radius by observation:
The center is