Question

An object in static equilibrium has a coefficient of static friction as 0.110. If the normal force acting on the object is 95.0 newtons, what is the mass of the object?

Answer 1

If the object of mass `m` lies on horizontal surface then its weight `mg` is the normal reaction `n`.

So `n=mg`

where

`n->"normal reaction"=95N`

`m->"mass of the object"=?`

`g->"acceleration due to gravity"=9.8ms^-2`

So `m=n/g=95/9.8=9.69kg`