What is the equation of the line that goes through #(5,1)# and has a slope of #m=4#?

2 Answers
Nov 19, 2016

#y=4x-19#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

Here #m=4" and " (x_1,y_1)=(5,1)#

#rArry-1=4(x-5)#

#rArry-1=4x-20#

#rArry=4x-19" is the equation"#

Nov 19, 2016

#y=4x-19#

Explanation:

use the equation

#(y-y_1)=m(x-x_1)#

#m=4" "(x_1,y_1)=(5,1)#

#(y-1)=4(x-5)#

#y-1=4x-20#

#:.y=4x-19#