Question

Given log4=0.6021, log9=0.9542, and log12=1.-792, how do you find log 108,000?

Answer 1

`log108000=5.0334`

Explanation:

`log108000=log(108xx1000)=log108+log1000`

= `3+log108`

= `3+log(4xx27)=3+log4+log27`

= `3+log4+log3^3`

= `3+log4+3log3`

Now we have `log4=0.6021` and as `log3^2=log9=0.9542`,

we have `2log3=0.9542` and hence `log3=0.9542/2=0.4771`

Hence `log108000=3+0.6021+3xx0.4771`

= `3.6021+1.4313`

= `5.0334`