How do you find the average rate of change of #1/x# over the interval [1, 4]?

2 Answers
Nov 21, 2016

# "average rate of change" = -1/4 #

Explanation:

The average rate of change of a function #f(x)# over an interval #[a,b]# is given by:
# "average rate of change" = ("change in y") / ("change in x") = ( f(b)-f(a) )/(b-a) #

So with # f(x)=1/x # over #[1,4]#
# "average rate of change" = ( f(4)-f(1) ) / (4-1) #
# :. "average rate of change" = (1/4-1) / 3 #
# :. "average rate of change" = (-3/4) / 3 #
# :. "average rate of change" = -1/4 #

Nov 21, 2016

#-1/4#

Explanation:

The average rate of change of a function over an interval between (a , f(a)) and (b ,f(b)) is the slope of the #color(blue)"secant line"# joining the 2 points.
That is.

#color(red)(bar(ul(|color(white)(2/2)color(black)((f(b)-f(a))/(b-a))color(white)(2/2)|)))#

here a = 1 and b = 4

#rArrf(1)=1" and " f(4)=1/4#

#rArr(1/4-1)/(4-1)=(-3/4)/3=-1/4larr" average rate of change"#