How do you solve #r+11+8r=29#?

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Answer 1 · 2016-11-21T22:43:42

#r = 2#

First, rearrange and combine like terms:

#r + 8r + 11 = 29#

#(1 + 8)r + 11 = 29#

#9r + 11 = 29#

Now we can isolate and solve for #r# while always keeping the equation balanced:

First, subtract #11# from each side of the equation:

#9r + 11 - 11 = 29 - 11#

#9r + 0 = 18#

#9r = 18#

Now we can divide each side of the equation by #9# to get #r#:

#(9r)/9 = 18/9#

#1r = 2#

#r = 2#