Question

How do you solve `\sqrt { ( 3x - 2) ^ { 2} } = 2- 3x`?

Answer 1

`sqrt((3x- 2)(3x - 2)) = 2 - 3x`

`3x - 2 = 2 - 3x`

`6x = 4`

`x = 2/3`

Hopefully this helps!