How do you solve #-2(2-2x)+2x=20#?

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Answer 1 · 2016-11-23T13:11:34

#x = 4#

Step 1) Expand the term within the parenthesis:

#(-2*2) + (-2*-2x) + 2x = 20#

#-4 + 4x + 2x = 20#

Step 2) Combine like terms:

#-4 + 6x = 20#

Step 2) Solve for #x# while keeping the equation balanced:

#-4 + 6x + 4 = 20 + 4#

#6x = 24#

#(6x)/6 = 24/6#

#x = 4#