Question

How do you differentiate `f(x)=sin(3e^(x^2)+1)` using the chain rule?

Answer 1

`f'(x)=6xe^(x^2)cos(3e^(x^2)+1)`

Explanation:

`f(x)=sin(3e^(x^2)+1)`

Use the chain rule to differentiate ("derivative of the outside times derivative of the inside"):

`f'(x)=cos(3e^(x^2)+1)(6xe^(x^2))`
`f'(x)=6xe^(x^2)cos(3e^(x^2)+1)`