Question

How do you find the center of `(x+2)^2+(y-3)^2=50`?

Answer 1

circle of centre `(-2,3)` and radius `sqrt(50)`

Explanation:

A circle of centre `(a,b)` and radius `r` has equation:

`(x-a)^2 + (y-b)^2=r^2`

Comparing with;

`(x+2)^2 + (y-3)^2=50`

We can see that this represents a circle of centre `(-2,3)` and radius `sqrt(50) (~~7)`

graph{(x+2)^2 + (y-3)^2=50 [-21.83, 18.17, -6.24, 13.76]}