How do you evaluate #abs(x+y)# when x=3, y=-5?
1 Answer
Nov 24, 2016
Explanation:
The
#color(blue)"absolute value"# denoted by the ' bars' can only ever have a#color(red)"positive value"# This is because it gives a measure of how far a number is from zero irrespective of it's sign.
That is
#|4|=|-4|=4# since 4 and - 4 are both 4 units from zero.Here
#|x+y|=|3+(-5)|=|3-5|=|-2|=2#