How to find mode of the following frequency distribution?

Class #color(white)(XXXXXXX)#Frequency#color(white)(XXX)#
#0-10color(white)(XXXXXXXX)22#
#10-20color(white)(XXXXXXxx)24#
#20-30color(white)(XXXXXXxx)36#
#30-40color(white)(XXXXXXxx)14#
#40-50color(white)(XXXXXXxx)12#

1 Answer
Nov 24, 2016

Mode is #23.53#

Explanation:

Let us first work out the cumulative frequency, which is as given below:

Class #color(white)(XXXXXXX)#Frequency#color(white)(XXX)#Cum. Frequency

#0-10color(white)(XXXXXXXX)22color(white)(XXXXXXXXXX)22#
#10-20color(white)(XXXXXXxx)24color(white)(XXXXXXXXXX)46#
#20-30color(white)(XXXXXXxx)36color(white)(XXXXXXXXXX)82#
#30-40color(white)(XXXXXXxx)14color(white)(XXXXXXXXXX)96#
#40-50color(white)(XXXXXXxx)12color(white)(XXXXXXXXXX)108#

As the highest frequency is #f_m=36#, whose modal class is #20-30# and class interval is #10#; the frequency just before is #f_(m-1)=24# and frequency just after is #f_(m+1)=14#.

Formula for Mode is #Mode=L_1+(f_m-f_(m-1))/(2f_m-f_(m-1)-f_(m-2))xxi#

#.:Mode=20+(36-24)/(2xx36-24-14)xx10#

= #20+12/34xx10=20+3.53=23.53#