Question

How do you write a cubic polynomial function with zeros -3, 2, and 1?

Answer 1

`f(x) = (x+3)(x-2)(x-1) = x^3-7x+6`

Explanation:

Multiply together linear factors with each of these zeros:

`f(x) = (x+3)(x-2)(x-1) = x^3-7x+6`

Any polynomial in `x` with these zeros will be a multiple (scalar or polynomial) of this `f(x)`.