How do you evaluate #4^2*4^2#?

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Answer 1 · 2016-11-26T14:55:44

#4^2 * 4^2 = 256#

This can be written as

#(4*4)*(4*4) => 16*16 => 256#

Answer 2 · 2016-11-26T15:10:26

#4^2 xx 4^2 = 4^4#

You can evaluate each factor and then multiply them, but you can also find the answer by using laws of indices.

Compare with

#x^2 xx x^2" "larr# bases are the same, add the indices

=#x^(2+2) = x^4#

#4^2 xx 4^2 = 4^(2+2) = 4^4#

#4^4 = 4xx4xx4xx4 = 256#