How do you evaluate #Sin(π/3)*tan(π/6)#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Mia Nov 27, 2016 #1/2# Explanation: #sin(pi/3)xxtan(pi/6)# #" "# #=sqrt3/2xxsqrt3/3# #" "# #=sqrt(3^2)/(2xx3)# #" "# #=3/(2xx3)# #" "# #=1/2# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 2453 views around the world You can reuse this answer Creative Commons License