Question

How do you differentiate `(y-1)^2+y-x=0`?

Answer 1

`(y-1)^2+y-x=0`

Implicitly differentiate (use the chain rule and power rule):
`2(y-1)(dy/dx)+dy/dx-1=0`

Simplify:
`dy/dx(2y-2)+dy/dx=1`

`dy/dx(2y-2+1)=1`

`dy/dx(2y-1)=1`

`dy/dx=1/(2y-1)`