Question #32891

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Answer 1 · 2016-11-28T07:00:43

see below

#tan^2x-sin^2x=sin^2xtan^2x#

Left Side : #=tan^2x-sin^2x#

#=sin^2x/cos^2x-sin^2x#

#=(sin^2x-cos^2xsin^2x)/cos^2x#

#=(sin^2x(1-cos^2x))/cos^2x#

#=(sin^2x sin^2x)/cos^2x#

#=sin^2x*sin^2x/cos^2x#

#=sin^2x tan^2x#

#:.=# Right Side