Question

If `f(x)= 1/x` and `g(x) = 1/x`, what is `f'(g(x))`?

Answer 1

`-x^2`

Explanation:

I'll assume no error in the statement of the question.

`f'(x) = -1/x^2`

Therefore,

`f'(g(x)) = -1/(g(x))^2 = -1/(1/x)^2 = -x^2`