How do you simplify #[(x^-3y^-5z)^4]^3/(x^6y^10z^2)^-6#?

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Answer 1 · 2016-12-03T16:40:42

#y^120z^24#

#[(x^-3y^-5z)^4]^3/ (x^6y^10z^2)^-6#

Most of solving this equation involves the rule:

#(x^a)^b=x^(ab)#

for example:

=#(x^-3y^-5z)^12/ (x^6y^10z^2)^-6#

and goes on to give us:

#(x^-36y^60z^12)/(x^-36y^-60z^-12)#

the other rule is:

#x^a/x^b=x^(a-b)#

and this gives us:

#x^0y^120z^24#

or more simply, #y^120z^24# since #x^0#=1