Question

How do you condense `2logx-(3logy+logz)`?

Answer 1

The condensed answer is `log((x^2)/(y^3z))`.

Explanation:

`2logx-(3logy+logz)`.

`=logx^2-(logy^3+logz)`.

`=logx^2-logy^3z`.

`=log((x^2)/(y^3z))`. (Answer).