How do you find the center and radius of the circle given #(x-3)^2+(y+7)^2=50#?

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Answer 1 · 2016-12-04T04:01:39

The center is #(3,-7)# and the radius is #5sqrt2#.

Find the center and radius of #(x-3)^2 + (y+7)^2=50#

The equation of a circle is #(x-h)^2 +(y-k)^2=r^2#

where #(h,k)=# the center and #r=# the radius.

#=> (h,k)=(3, -7)# (note that the signs are opposite of the signs inside the parentheses)

#r^2=50#

To find r, square root both sides

#sqrt(r^2)=sqrt50#

#r=sqrt(25*2)#

#r=5sqrt2#