How do you convert the polar equation $r = 5 sec θ$ $r=5sectheta$ into rectangular form?

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Answer 1 · 2016-12-05T04:56:41

Please see the explanation.

Multiply both sides by $cos (θ)$ $cos(theta)$ :

$r cos (θ) = 5 sec (θ) cos (θ)$ $rcos(theta) = 5sec(theta)cos(theta)$

Use the identity $sec (θ) cos (θ) = 1$ $sec(theta)cos(theta) = 1$ :

$r cos (θ) = 5$ $rcos(theta) = 5$

Substitute x for $r cos (θ)$ $rcos(theta)$ :

$x = 5$ $x = 5$

How do you convert the polar equation r=5secthetar=5secθr=5sectheta into rectangular form?