How do you solve #abs(- 4x - 5) + 7= 10#?

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Answer 1 · 2016-12-05T08:43:45

#x=-2 or x=-1/2#

You can get the equivalent equation:

#|-4x-5|=3#

and then consider that it's solved by:

#-4x-5=+-3#

whose solutions are given by:

#4x=-5-3 or 4x=-5+3#

then #x=-2 or x=-1/2#