Question

Question #1b8ac

Answer 1

`(csc x- cot x)(sec x+1)`

`=(sinx(csc x- cot x)cosx(sec x+1))/(sinxcosx)`

`=((sinxcsc x- sinxcot x)(cosxsec x+cosx))/(sinxcosx)`

`=((1- cos x)(1 +cosx))/(sinxcosx)`

`=(1- cos^2 x)/(sinxcosx)`

`=sin^cancel2 x/(cancelsinxcosx)=sinx/cosx=tanx`