The gas inside of a container exerts #12 Pa# of pressure and is at a temperature of #650 ^o K#. If the temperature of the gas changes to #220 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-12-05T17:27:45

The new pressure is #=15.8Pa#

We use Gay Lussac's Law

#P_1/T_1=P_2/T_2#

#P_1=12Pa#

#T_1=650K#

#T_2=220+273=493K#

#P_2=(P_1T_2)/T_1#

#=12*650/493=15.8Pa#