Question

How do you factor `-x ^ { 2} - 4x - 2`?

Answer 1

`(-x^2-4x-2)=(-x+sqrt2+2)(x+sqrt2-2)`

Explanation:

`x=(-b+-sqrt(b^2-4ac))/(2a)=(4+-sqrt(-4^2-4(-2)(-1)))/-2=(4+-sqrt(8))/-2=(4+-2sqrt2)/-2=sqrt2+-2`