How do you solve #x^2 + 3x -2=0#?

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Answer 1 · 2016-12-06T00:55:37

#x^2+3x-2=0# is a quadratic equation in the form #ax^2+bx-2=0# where #a=1#, #b=3#, and #c=-2#.

To solve this equation we can use the quadratic formula.

#x=(-b+-sqrt(b^2-4ac))/(2a)#

Plug the given values into the formula.

#x=(-3+-sqrt(3^2-4*1*-2))/(2*1)#

#x=(-3+-sqrt(9+8))/2#

#x=(-3+-sqrt17)/2#

#x=(-3+sqrt17)/2, (-3-sqrt17)/2#