How do you find #[fog](x)# and #[gof](x)# given #f(x)=2x-3# and #g(x)=x^2-2x#?

Question

76869 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-06T15:50:06

The answers are #f@g(x)=2x^2-4x-3#
And #g@f(x)=(2x-3)(2x-5)#

#f(x)=2x-3#

#g(x)=x^2-2x#

#=f(g(x))=f(x^2-2x)=2(x^2-2x)-3#

#=2x^2-4x-3#

#g@f(x)=g(f(x))=g(2x-3)=(2x-3)^2-2(2x-3)#

#=(2x-3)(2x-3-2)#

#=(2x-3)(2x-5)#

#f@g(x)!=g@f(x)#