How do you solve the system of equations #2x + y = 6# and #- 2x - y = 6#?

1 Answer
Dec 7, 2016

There is no solution to this system of equations

Explanation:

#color(purple)("For there to be a solution the lines have to cross at some point.")#

Given:#" "2x+y=6" "...................Equation(1)#
#" "-2x-y=6" "...................Equation(2)#

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#color(blue)("Consider equation(1)")#

Subtract #color(red)(2x)# from both sides

#color(green)(2x+y=6" "->" "2xcolor(red)(-2x) +y=color(red)(-2x)+6#

#" "0+y=-2x+6#
#" "y=-2x+6..Equation(1_a)#

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#color(blue)("Consider equation(2)")#

Add #y# to both sides#" "->" "-2x=6+y#

Subtract 6 from both sides#->" "-2x-6=y#

Write as: #" "->" "y=-2x-6..Equation(2_a) #

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Compare both #Equation(1_a)" and "Equation(2_a)# to the standard straight line equation form of #y=mx+c#

Note that #m# is the slope (gradient) of the line

This means that both equations have the same slope of -2 (from #-2x#) thus they are parallel.

Now consider the value of #c" in "y=mx+c#
In one equation it is +6 and in the other it is -6.

So they cross the y-axis in different places. Thus the lines never cross each other and as a consequence do not share values. So there is no solution to this system of equations.