Question

The gas inside of a container exerts `15 Pa` of pressure and is at a temperature of `180 ^o K`. If the pressure in the container changes to `36 Pa` with no change in the container's volume, what is the new temperature of the gas?

Answer 1

The new temperature is `432K`

Explanation:

We use Gaylussac's Law

`P_1/T_1=P_2/T_2`

`P_1=15Pa`

`T_1=180K`

`P_2=36Pa`

`T_2=(P_2T_1)/P_1`

`=36*180/15=432K`