Question

The gas inside of a container exerts `72 Pa` of pressure and is at a temperature of `450 ^o K`. If the temperature of the gas changes to `90 ^oC` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

The new pressure is `=58.1Pa`

Explanation:

Use Gay Lussac's Law

`P_1/T_1=P_2/T_2`

`P_1=72Pa`

`T_1=450K`

`T_2=90+273=363K`

`P_2=(P_1T_2)/T_1`

`=72*363/450=58.1 Pa`