Question

How do you evaluate `abs(p+q)div5` when p=-2, q=-3?

Answer 1

`|(-5)|-:5=5-:5=1`

Explanation:

The quantity inside an absolute value sign is given as positive. So let's substitute in the values for `p` and `q`, evaluate the absolute value, and then divide by 5:

`|p+q|-:5`

`|(-2)+(-3)|-:5`

`|(-5)|-:5`

`5-:5`

`1`