What is the radius of the circle #x^2 +y^2=7/4#?

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Answer 1 · 2016-12-09T17:46:35

The radius is #=sqrt7/2=1.32#

The general equation of a circle is

#(x-a)^2+(y-b)^2=r^2#

The center is #(a,b)# and the radius is #=r#

Here,

#x^2+y^2=(sqrt7/2)^2#

This is a circle, center #(0,0)# and radius #=sqrt7/2#

graph{x^2+y^2=7/4 [-10, 10, -5, 5]}