How do you solve #\frac { 6} { 7x } = \frac { 4} { 5x - 1}#?

1 Answer
Dec 9, 2016

Multiply the fractions on each side of the equation by the same factor, which is the product of the denominators (#7x(5x - 1)#), to clear the fractions and keep the equation balanced:

#(7x(5x - 1) * 6)/(7x) = (7x(5x - 1)*4)/(5x - 1)#

#(cancel(7x)(5x - 1) * 6)/(cancel(7x)) = (7xcancel((5x - 1))*4)/cancel((5x - 1))#

#(5x -1)*6 = 7x*4#

We can now solve for #x# using the necessary mathematics while keeping the equation balanced:

#30x - 6 = 28x#

#30x - 28x - 6 + 6 = 28x - 28x + 6#

#2x = 6#

#(2x)/2 = 6/2#

#x = 3#