Question

What is the pressure in a 10.0-L cylinder filled with 0.460 mol of nitrogen gas at a temperature of 314 K?

Answer 1

Approx. `1*atm`. We use the Ideal Gas equation.........

Explanation:

`P=(nRT)/V=(0.460*cancel(mol)xx(0.0821*cancelL*atm)/(cancelK*cancel(mol))xx314*cancelK)/(10.0*cancelL)`

`=` `??atm`