The value of #y# varies directly with #x#. When #y=35, x=1/2#. What is the value of #y# when #x=2 1/4#?

1 Answer
Dec 10, 2016

Here's the explanation.

Explanation:

Given that, #y# varies directly with #x#.
So, #ypropx#.
#:.y=kx#. [#k# is the dimensionless constant of proportionality].

Now, from the initial given values of #x# & #y#:
#y=kx#
#:.35=kxx1/2#.
#:.k=70#.

So, when value of #x# becomes #2(1/4)#, the value of #y# becomes:

#y=kxxx#.
#:.y=70xx9/4#.
#:.y=157.5#. (Answer).

Hope it Helps :)