Question

How do you use the chain rule to differentiate `y=(x+1)^(-1/2)`?

Answer 1

The answer is `=-1/2(x+1)^(-3/2)`

Explanation:

The function is `=u^(-1/2)`

We use `(x^n)'=nx^(n-1)`

The derivative is `=(u^(-1/2))'=-1/2u^(-3/2)*u'`

Here, `y=(x+1)^(-1/2)`

`dy/dx=-1/2(x+1)^(-3/2)*1`